- #1

ILoveBaseball

- 30

- 0

[tex]x(t) = t^2+30t-11[/tex]

[tex]y(t)=t^2+30t+38[/tex]

How many units of distance are covered by the point P(t) = (x(t),y(t)) between t=0, and t=9 ?

well since the bounds are already given (0->9), i just need help on setting up the integral. here's what i done:

[tex]dx/dt = 2t+30[/tex]

my integral:

[tex]\int_{0}^{9}(t^2+30t+38)*(2t+30)[/tex]

but i get the incorrect answer when i integral it, can someone help me set it up?