- #1

- 52

- 0

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance dont help at all if I dont know average velocity...

- Thread starter 404
- Start date

- #1

- 52

- 0

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance dont help at all if I dont know average velocity...

- #2

- 40

- 0

u have accel, v1, and distance

use (v2)^2= (v1)^2 + 2ad

use (v2)^2= (v1)^2 + 2ad

- #3

OlderDan

Science Advisor

Homework Helper

- 3,021

- 2

Force times distance in the direction of the force is work, and that equals change in kinetic energy.404 said:

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance dont help at all if I dont know average velocity...

Edit

OOPs.. two suggestions flying at the same time. They both lead to the same conclusion.

- #4

- 52

- 0

Ok I see, thanks.

- Replies
- 2

- Views
- 1K

- Replies
- 3

- Views
- 4K

- Replies
- 1

- Views
- 1K

- Replies
- 4

- Views
- 15K

- Replies
- 4

- Views
- 1K

- Replies
- 6

- Views
- 29K

- Replies
- 15

- Views
- 2K

- Replies
- 2

- Views
- 4K

- Replies
- 1

- Views
- 13K

- Replies
- 5

- Views
- 25K