- #1

- 52

- 0

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance dont help at all if I dont know average velocity...

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter 404
- Start date

- #1

- 52

- 0

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance dont help at all if I dont know average velocity...

- #2

- 40

- 0

u have accel, v1, and distance

use (v2)^2= (v1)^2 + 2ad

use (v2)^2= (v1)^2 + 2ad

- #3

OlderDan

Science Advisor

Homework Helper

- 3,021

- 2

404 said:

I found the acceleration to be 6.15*10^15 m/s^2, which is confirmed by the answer book, but how can I get the final velocity without change in time? distance dont help at all if I dont know average velocity...

Force times distance in the direction of the force is work, and that equals change in kinetic energy.

Edit

OOPs.. two suggestions flying at the same time. They both lead to the same conclusion.

- #4

- 52

- 0

Ok I see, thanks.

Share:

- Replies
- 4

- Views
- 16K

- Replies
- 3

- Views
- 4K

- Replies
- 2

- Views
- 4K