# Find energy dissipated due to air friction in a thrown ball

A 0.40 kg ball is thrown vertically upward with a speed of 30 m/s. The ball reaches a height of 40 m. Assuming g= 9.8 m/s^2, the energy dissipated due to air friction is :

F=mgh m=0.40kg, g=10 m/s^2, h=40m, a= 30 m/s

Not sure if I set this problem up right, and since everything is given don't know how to find energy dissipated due to friction.

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OlderDan
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Gashouse said:
A 0.40 kg ball is thrown vertically upward with a speed of 30 m/s. The ball reaches a height of 40 m. Assuming g= 9.8 m/s^2, the energy dissipated due to air friction is :

F=mgh m=0.40kg, g=10 m/s^2, h=40m, a= 30 m/s

Not sure if I set this problem up right, and since everything is given don't know how to find energy dissipated due to friction.
Can you calculate the initial energy of the ball, and the energy it has when it reaches the highest point?

F is not mgh. mgh is potential energy.
30 m/s is not acceleration, it is the initial velocity.