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A 0.40 kg ball is thrown vertically upward with a speed of 30 m/s. The ball reaches a height of 40 m. Assuming g= 9.8 m/s^2, the energy dissipated due to air friction is :
F=mgh m=0.40kg, g=10 m/s^2, h=40m, a= 30 m/s
Not sure if I set this problem up right, and since everything is given don't know how to find energy dissipated due to friction.
F=mgh m=0.40kg, g=10 m/s^2, h=40m, a= 30 m/s
Not sure if I set this problem up right, and since everything is given don't know how to find energy dissipated due to friction.