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Find equation of tangent line

  1. Oct 29, 2007 #1
    i would like to know if my answer is correct can someone tell me the results for this:
    Find the equation of the tangent line to x^3-2x^2y+y^2=17 at (2,-1)

    ive gotten y'=(3x^2+4xy)/(-2x^2-y)
    and my line equations is
    y+1=(-1/4)(x-2)
    thanks in advance
     
    Last edited: Oct 29, 2007
  2. jcsd
  3. Oct 29, 2007 #2

    Dick

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    I think you have some sign problems in your derivative. Check again.
     
  4. Oct 29, 2007 #3
    i did it wrong i re did it and got this:
    dy/dx=-3x^2+4xy^2/-4x^2+2y

    is that correct?
     
  5. Oct 29, 2007 #4

    Dick

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    The signs have improved, but you have bad exponent in the numerator and a bad coefficient in the denominator. I think if you do it once more carefully, you'll get it.
     
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