- #1
andrey21
- 476
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Find the equation of the straight line which is perpendicular to the plane
4x+3y+2z=1
Which goes through the point (1,1,7)
Is the point (5,7,15) on this line?
By inspection we can see direction of the normal to the plane:
(4,3,2)
Therefore equation of straight line is:
r(t) = (1,1,7) + t (4,3,2)
Now I need to establish a value for t, however when I substitute in values for x,y,z I obtain:
t=1
t=2
t=4
Any help would be great thank you
4x+3y+2z=1
Which goes through the point (1,1,7)
Is the point (5,7,15) on this line?
By inspection we can see direction of the normal to the plane:
(4,3,2)
Therefore equation of straight line is:
r(t) = (1,1,7) + t (4,3,2)
Now I need to establish a value for t, however when I substitute in values for x,y,z I obtain:
t=1
t=2
t=4
Any help would be great thank you