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help me to solve this problem
find exponential function f(x)=Ca^x with the 2 given points (0,5)(2,5/9)
find exponential function f(x)=Ca^x with the 2 given points (0,5)(2,5/9)
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Alright, [itex]f(x)=Ca^x[/itex], f(0)=5, and f(2)=5/9. So you have two equations and two unkowns: a and C. You can write the first equation as:linhthuy256 said:plz help me to solve this problem
find exponential function f(x)=Ca^x with the 2 given points (0,5)(2,5/9)
thankzzzzzzzzzz..........
beside i still have 1 more problem that is really need help will u able to help me plz?linhthuy256 said:yes and the function f(x)=5*1/3^x that's what i had got before but when i put down in the answer and it said "wrong", can u help me ??
yes i did every single posible way but it stills said "wrong" or the answer is not accepted.linhthuy256 said:beside i still have 1 more problem that is really need help will u able to help me plz?
Alright, what's the other problem?linhthuy256 said:beside i still have 1 more problem that is really need help will u able to help me plz?
What was the exact phrasing of the problem?linhthuy256 said:yes i did every single posible way but it stills said "wrong" or the answer is not accepted.
No, that's not right, in fact niether function passes through that point. You could graph the two functions in a different window to find the true intersection, but it is clear by inspection that x=5 will yield 5^5 in both cases. As for the second case, just graph 400x^5 instead of x^5 and see where this intersects g(x).linhthuy256 said:and the other problem is
compare the functions f(x)=x^5 and g(x)=5^x by graphing both f and g in several viewing rectangles.
a) find the x-coordinates of the point intersectionof the two curves accurate to two decimal places. and i did the graphing w/ a result of (1.70,1.70) is that rite?
and part b) find the value of x greater than 5 for which g(x)=400 f(x)
it's still have no intersection point between 10 or 12-13LeonhardEuler said:Look between x=10 and x=12. y will be between 10^6 and 10^8.
i give up i did as wat u say for both first and second curve but still it doesn't show any intersection point when i go between x=1 and up to x=25LeonhardEuler said:Yes. Go to the "range" window. Put xmin as 10, xmax as 12, ymin as 10^6, and ymax as 10^8. Then just use the intersection feature. Alternitivley, just keep guessing values for x. g(x) starts out smaller than f(x) and then gets bigger. So, if you put in a certain x value and g(x) is smaller than 400x^5, try a bigger x. If g(x) is to big, try a smaller x.