- #1
Fusilli_Jerry89
- 159
- 0
A particle moves in a line so its position at any time in t ≥0 is given by the function s(t)=t²-6t+5,
where s is measured in meres and t is measured in seconds.
a) find the displacement during the first 6 seconds.
All i did was input 0 into the equation solve, then do the same with 6 and subtract the two. I got 0. Is this the right way to do that, os is that too "physics like"?
b)Find avg. velocity during first 6 seconds.
i basically did the same thing with (y2-y1)/(x2-x1) and got 0.
c) Find instantaneous velocity when t=4.
the derivative of the function is 2t-6 so:
s(4)=2(4)-6
=2
d) Find the acceleration of the particle when t=4
the derivative of 2t-6 is 2 so is it 2?
e) At what values does the particle change direction?
I got when t=3 but only by looking at the graph. How do you do this by calculus?
f) Where is the particle when s is a minimum?
again by using the graph
where s is measured in meres and t is measured in seconds.
a) find the displacement during the first 6 seconds.
All i did was input 0 into the equation solve, then do the same with 6 and subtract the two. I got 0. Is this the right way to do that, os is that too "physics like"?
b)Find avg. velocity during first 6 seconds.
i basically did the same thing with (y2-y1)/(x2-x1) and got 0.
c) Find instantaneous velocity when t=4.
the derivative of the function is 2t-6 so:
s(4)=2(4)-6
=2
d) Find the acceleration of the particle when t=4
the derivative of 2t-6 is 2 so is it 2?
e) At what values does the particle change direction?
I got when t=3 but only by looking at the graph. How do you do this by calculus?
f) Where is the particle when s is a minimum?
again by using the graph