Find Intercepts if any

1. Jan 7, 2008

catteyes

1. The problem statement, all variables and given/known data

y=x^2[SQ.RT.(9 - x^2)]

2. Relevant equations

3. The attempt at a solution

0= x^2 (+/- 3 - x)
0=x(x+3)(x-3)
x=0
x=3
x=-3

y=0[SQ.RT.(9-0)]
y=SQ.RT.(9)
y=+/-3
y= 3
y=-3
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Jan 7, 2008

rocomath

This question should be posted in the Precalculus subforum.

Anyways, your question is find the x-int & y-int of $$y=x^2\sqrt{9-x^2}$$ correct?

Your procedure for finding the y-int are correct, but your work in finding the x-int is wrong.

You have $$\sqrt{9-x^2}$$ you cannot just take the square root, but your answers are right.

$$0=x^2\sqrt{9-x^2}$$

$$x^2=0$$
$$\sqrt{9-x^2}=0$$

Last edited: Jan 7, 2008
3. Jan 7, 2008

EnumaElish

The X-axis intercepts are x=0, x=3, x=-3.