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Find Intercepts if any

  1. Jan 7, 2008 #1
    1. The problem statement, all variables and given/known data

    y=x^2[SQ.RT.(9 - x^2)]

    2. Relevant equations



    3. The attempt at a solution

    0= x^2 (+/- 3 - x)
    0=x(x+3)(x-3)
    x=0
    x=3
    x=-3



    y=0[SQ.RT.(9-0)]
    y=SQ.RT.(9)
    y=+/-3
    y= 3
    y=-3
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jan 7, 2008 #2
    This question should be posted in the Precalculus subforum.

    Anyways, your question is find the x-int & y-int of [tex]y=x^2\sqrt{9-x^2}[/tex] correct?

    Your procedure for finding the y-int are correct, but your work in finding the x-int is wrong.

    You have [tex]\sqrt{9-x^2}[/tex] you cannot just take the square root, but your answers are right.

    [tex]0=x^2\sqrt{9-x^2}[/tex]

    [tex]x^2=0[/tex]
    [tex]\sqrt{9-x^2}=0[/tex]
     
    Last edited: Jan 7, 2008
  4. Jan 7, 2008 #3

    EnumaElish

    User Avatar
    Science Advisor
    Homework Helper

    The X-axis intercepts are x=0, x=3, x=-3.

    (Start with:

    0 = x^2 sqrt[(x+3)(x-3)].

    Hint: Square both sides.)

    The Y-axis intercept(s) are easier to solve: the are found by substituting x = 0 into the formula.
     
    Last edited: Jan 7, 2008
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