1. The problem statement, all variables and given/known data Graph f(x) = sqrt(x^2 - 2x), and find an interval on which it is one-to-one. Find the inverse of the function restricted to that interval. 2. Relevant equations 3. The attempt at a solution What I can't do is really finding the inverse function. It seems very simple, but somehow I got stuck in the process. swap x and y in the original function y = sqrt(x^2-2x) x = sqrt(y^2-2y) and solve for y so i did x^2 = y^2-2y, and i tried to factor out y x^2 = y(y-2) x^2/y-2 = y now i am really stuck. how can i pull that y out? Thank you for any kind of help!!! ---- edited I was thinking about this formula: d/dy f-1(x) = 1/ f ' (y) i guess i can then integrate the d/dy f-1(x) and get f-1(x)? so i started working again f ' = (1/2 (x^2-2x) ^-1/2) * 2x-2 so 1/f ' =[ 2 (x^2-2x)^1/2 ]/ 2x-2 which is d/dy f-1 but the integration doesn't work!