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Find [tex]\mathop {\lim }\limits_{x \to 0} \frac{{\tan (nx) - n\tan (x)}}
{{n\sin (x) - \sin (nx)}} [/tex]
{{n\sin (x) - \sin (nx)}} [/tex]
Which, again, is just another form of applying small angle approximation/l'hopital/taylor series =Dexploit the heck out of
lim u->0 (sin u)/u = 1 .