A ball of mass 350g is travelling with a speed of 4m/s when it hits at right angles a fixed vertical wall. The ball rebounds with a speed of 3m/s. Find the magnitude of the impulse exerted by the ball on the wall. Using a simple diagram show the direction of velocities and the impulse.
m = 350g or m = 0.35kg v1 = - 4m/s^-1 v2 = 3m/s^-1
Magnitude = mv2 – mv1
The Attempt at a Solution
Magnitude = 0.35 3 – 0.35(- 4)
Magnitude = 1.05 – 1.4
Magnitude = - 0.35
Hi can some one check this equation for me please.
Also is there a unit to simbolize magnitude? and is the final answer 0.35 given in joules???
Last one how would i draw a simple diagram showing the direction of velocities and the impulse???