- #1
giokrutoi
- 128
- 1
Homework Statement
(22016+ 5)m + 22015 = 2n + 1[/B]
find every n and m pairs
as they are positive integers
The Attempt at a Solution
(22016+ 5)0 + 22015 = 22015 + 1[/B]
so one pair is m= 0 , n = 2015
if m =1 the equation is meaningless
if m> 1 so there are really amount of powers that can't be handled by n as 1 in the end of the equation is needed to cancel out 5^m so 5^m -1 can't be equal to 2^n
so the equation has only one answer
am i right ?