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Find out the time and velocity

  1. Jul 12, 2005 #1
    A ball is thrown verticaly from the ground .Find out the time and velocity when the ball reach 10 and 40m from the ground. The time given between 10m and 40m is 4s.
    I tried to solve this question by asumming that t30 = t10 + 4s and I found that the value of v30 is negative. So I try another way to solve it. This time I do not assume t30 = t10 + 4s. I find out all the values besides t first and finally I got the value of v30 is positive . However, t30 is not equal to t10 + 4s .
    :grumpy: :grumpy: :grumpy:
    What`s wrong actually??
     
  2. jcsd
  3. Jul 12, 2005 #2

    Galileo

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    Nothing may be wrong. If you chose the positive direction downwards, then v will be negative. What equation did you use?
     
  4. Jul 12, 2005 #3
    Try assuming that the ball was thrown from the 10m mark up to the 40m mark instead of from ground. You know the distance between (40-10), the time between, and the acceleration. All you need is the initial velocity. You should have an equation for that. Once you find the initial velocity (which, from what you just solved is actually the velocity at 10m), this velocity becomes the final velocity. You also have the distance and acceleration. You need to then find the initial velocity (this time refering to the ground). Good luck.
     
  5. Jul 12, 2005 #4
    To find the velocity at d=10m use

    change in displacement = v(initial)t + .5at^2


    From there, you can find the velocity at d=40 from

    v(final)^2 = v(initial)^2 + 2a(change in displacement)
     
  6. Jul 12, 2005 #5
    I think there must be something wrong...since i get positive value of v10 but negative value of v30.
     
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