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Find oxidation number of platinum

  1. Aug 4, 2012 #1
    1. The problem statement, all variables and given/known data
    Hello...

    Seems like an easy question, but I'm notquite sure though.

    Find the oxidation number of platinum in the following compound:

    Pt(NH3)2Cl(NO2)


    2. Relevant equations



    3. The attempt at a solution

    If I just put Pt = x, and I know that (NH3) is neutral = 0, and Cl = -1, the one thing that is bothering me is the (NO2). If it was alone, you will know that N had oxidation number +4. But here it is in another compound. Usually O is -2 and N is -3, but that gives me a total of -7 for that, and with the Cl = -1, I have a total of +8 for Pt, which I'm pretty sure is incorrect.
    What am I missing ? :)


    Regards
     
  2. jcsd
  3. Aug 4, 2012 #2

    chemisttree

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    NO2 is the nitrite anion.
     
  4. Aug 4, 2012 #3
    Of course :/

    So simple.

    Thank you :)
     
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