# Find P

1. Oct 4, 2004

### rajesh

P corresponds to prime digits(i donno what thi means.....i am giving exactly as given in a test)

7P5
x33
---------
PPPP
PPPP
----------
PPPPP

Find the value of P?

2. Oct 4, 2004

### Rogerio

Let's suppose P is a string of digits.
From 5x3 -> P ends in a '5'
From PPPP+PPPP = PPPPP -> P ends in a '0'

So it's impossible.

3. Oct 4, 2004

### rajesh

actually i could not put the correct indentation(i am new to this site)....

somebody tell me how to attach a file

4. Oct 4, 2004

### Gokul43201

Staff Emeritus
Is this what you want ?

Code (Text):

7 P 5
x 3 3
---------
P P P P
P P P P
----------
P P P P P

5. Oct 4, 2004

### Gokul43201

Staff Emeritus
Even with the indentation (enclose within [ code] [ /code] tags), there would be no solution, as you would have PPPP + PPPP0 = PPPPP.

Why is this impossible ?

PPPP -> 1000P+100P+10P+P = 1111P and similarly PPPP0 ->11110P, so adding should give 12221P, but clearly PPPPP -> 11111P, a contradiction, unless P=0. But clearly P can't be 0.

6. Oct 4, 2004

### Gokul43201

Staff Emeritus
I think you haven't copied the problem down correctly....

Here's another reason why this is wrong (if you're not happy with the previous ones) :

700 X 33 = 23100
800 X 33 = 26400

So clearly 7P5 X 33 must be in the 2 thousands, therefore P must be 2. But also, any multiple of 5 must end with 5, so P must be 5. A contradiction !

Last edited: Oct 4, 2004