1. The problem statement, all variables and given/known data A 90Ω resistor, a 32 mH inductor, and a 5μF capacitor are connected in series across the terminals of a sinusoidal voltage source Vs = 750cos(5000t + 30)V. Calculate the phasor current. [Broken] 2. Relevant equations phasor current i = V/Z V in polar form = (Magnitude)(cos a + j sin a) Z (inductor) = wLj Z (capacitor) = -j/ωC Z (resistor) = r total impedance = Z inductor + Z capacitor + Z resistor Conversion to other form of Z: Z(mag) = (R2+X2)1/2 Z angle = tan-1(R/X) from the form Z = R + jx 3. The attempt at a solution Not sure how I would convert the voltage to polar form and then I could find the current. But for the impedance it would be: ω = 5000, so, Z (inductor) = 5000*(32 x 10-3) = 160j Z (capacitor) = -1j/(5000*(5 x 10-6)) = -40j Z (r) = 90Ω So Z = 90 +120jΩ Then to polar form would be Z(mag) = (R2+X2)1/2 Z(angle) = tan-1(R/X) So Z(mag) = 150 Z(angle) = 36.8 deg Z = 150 ∠ 36.8 degrees, for sure Now for the voltage I'm not so sure, but I'm guessing the angle is just 30 so V = 750∠30 deg So if the voltage is correct then would the phasor current be I = (750∠30 deg) / (150 ∠ 36.8 deg) I = (5 ∠ -6.8 deg)A ? Thank you.