Find position of two masses at any time

So in summary, we have a system of two particles connected by a massless spring, one initially resting on a table and the other held vertically above it. The first particle is projected upwards with an initial velocity. We need to find the positions of the two masses at any time and describe their motion. To do this, we use the center of mass formula for the kinetic energy and consider two separate potentials, one for gravity and one for the spring. After solving the Lagrangian, we will be given equations of motion for each particle which can be integrated to find the positions of the masses at any time.
  • #1
leonne
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Homework Statement


2 particles are joined by mass less spring of length L. m2 initially resting on table and i am holding m1 vertically above m2 at height L. I project m1 vertically upwards with initial velocity Vo
find position of the two masses at any time and describe motion

Homework Equations


L=t-u

The Attempt at a Solution


I just need help finding the kinetic and potential of the system.
ok so in this system we have 2 potentials right? One is gravity and the other is the spring?
For the kinetic, we use the center of mass?

they get L= 1/2(M[tex]\stackrel{.}{Y}[/tex]2-MgY+ 1/2([tex]\mu[/tex][tex]\stackrel{.}{y}[/tex]2-1/2(k(y-L)2)

for kinetic we use the center of mass formula right t=1/2MR2 +1/2([tex]\mu[/tex]r2

Why exactly do they have Y than y is Y for mass 1 and y for mass 2? If so than the two potentials, one of them acts on one block and the other one on the other block?

o also how do we know when to use the center of mass formula? there was another problem with pendulum in a moving elevator and didn't use the center of mass formula

ok and to find position of the two masses, after solving the Lagrangian you are given equation of motion and i would think just take the derivative but that's not posible from the answer they get
Thanks
 
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  • #2
Yes you are right, Y is for mass 1 and y is for mass 2. The two potentials act on the two blocks separately, one is the gravitational potential (acting on both) and the other is the potential of the spring (acting only on the second block).For the center of mass formula, it is used when you have a system with more than one particle, in this case two particles. The elevator problem is a single particle system so the center of mass formula does not apply.To find the position of the two masses, after solving the Lagrangian you will be given equations of motion for each particle. To find the positions of the two masses at any time, you just need to integrate these equations.
 

1. What is the equation for finding the position of two masses at any time?

The equation for finding the position of two masses at any time is given by Newton's Law of Gravitation: F = G * (m1 * m2) / r^2, where F is the force of attraction between the two masses, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

2. How do you determine the initial position and velocities of the two masses?

The initial positions and velocities of the two masses can be determined by using the laws of conservation of momentum and energy. By setting up equations that equate the initial kinetic and potential energies of the system to the final kinetic and potential energies, you can solve for the initial velocities and positions of the two masses.

3. Can this equation be used to find the position of two masses in a non-gravitational system?

No, this equation is specifically for finding the position of two masses in a gravitational system. For non-gravitational systems, other equations and principles, such as electric or magnetic forces, would need to be used to find the positions of the two masses.

4. Can this equation be used for more than two masses?

Yes, this equation can be extended for more than two masses by taking into account the forces and distances between each individual mass. The equation would then become: F = G * (m1 * m2) / r12^2 + (m1 * m3) / r13^2 + (m2 * m3) / r23^2, where r12 is the distance between masses 1 and 2, r13 is the distance between masses 1 and 3, and r23 is the distance between masses 2 and 3.

5. What are the limitations of this equation?

This equation assumes that the two masses are point masses, meaning that their size and shape are negligible. It also assumes that there are no external forces acting on the system. In reality, these assumptions may not hold true, so the calculated positions may not be completely accurate. Additionally, this equation does not take into account relativistic effects or the influence of other celestial bodies, which may also affect the positions of the two masses.

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