- #1

Saladsamurai

- 3,020

- 7

## Homework Statement

Find Radius of Convergence of the corresponding power series solution from Recursion Equation alone:

[tex]n^2a_{n+2} - 3(n+2)a_{n+1} +3a_{n-1} = 0 \qquad(1)[/tex]

## Homework Equations

R = 1/L where

[tex] L = \lim_{n\rightarrow\infty}\left|{\frac{a_{k+1}}{a_k}\right|\qquad(2)[/tex]

## The Attempt at a Solution

I was thinking that I could solve (1) for a

_{n+1}and then solve it again for a

_{n}and then use the ratio in (2). But I feel like that might be a very illegal move.

Thoughts on this?