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Find roots of a function

  1. Jul 20, 2012 #1
    What are the 4 roots of a function y^2 = x^3 + x + 6 (mod 5 * 9^2)?

    I don't know where to start a problem like this. The roots mod 5 are (0,1) (0,4) (2,1) (2,4) (3,1) (3,4) (4,2) (4,3) if that helps
     
  2. jcsd
  3. Jul 20, 2012 #2

    jedishrfu

    Staff: Mentor

    is this a function of the form

    g(x,y) = x^3 + x + 6 * (mod 5 * 9^2) - y^2
     
  4. Jul 20, 2012 #3
    I think it is meant to be in the form I posted
     
  5. Jul 20, 2012 #4

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    What you posted is not a "function", it is an "equation". It would be equivalent to
    f(x)= 0 where f is the function jedishrfu gave.
     
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