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Find specific heat capacity

  1. Nov 18, 2014 #1
    1. The problem statement, all variables and given/known data
    When 1.25 kg of a cold metal at a temperature
    of 263 K was immersed in 1.43 kg of water at
    a temperature of 365 K, the final temperature
    was 336 K. What is the specific heat capacity
    of the metal?

    2. Relevant equations
    Q=mc∆t
    -Q=Q


    3. The attempt at a solution
    The answer should be 1.90KJ(kg*K)
     
    Last edited: Nov 18, 2014
  2. jcsd
  3. Nov 18, 2014 #2

    rude man

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    Homework Helper
    Gold Member

    Heat gained by metal = heat lost by water.
     
  4. Nov 19, 2014 #3

    CWatters

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    Science Advisor
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    That's not an attempt at a solution.
     
  5. Nov 19, 2014 #4
    And there are a couple of typos as well, it should be written as 1.90 kJ/(kgK)
     
    Last edited: Nov 19, 2014
  6. Nov 19, 2014 #5
    Well, you have the right equation there. How much will the temperatures change?
     
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