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does anyone know how to find the square root of 5+12i ?

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does anyone know how to find the square root of 5+12i ?

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Hurkyl

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Can you find a number z such that z*z = 5 + 12i?

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That sounds easier but im not sure how to figure that out.Hurkyl said:

Can you find a number z such that z*z = 5 + 12i?

This was a multiple choice question so the answer is 2+i

I dont know how they got that!!

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Actually... no, that's wrong. The answer is 3 + 2i.aisha said:This was a multiple choice question so the answer is 2+i

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Hurkyl

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You say one of the choices was 2+i. Well, what is (2+i)*(2+i)? Is it 5+12i?

Do you know of a way to write down an arbitrary complex number, z, in terms of two (real) variables? If so, then you can compute what z^2 is...

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can u plz tell me how you got that answer?phreak said:Actually... no, that's wrong. The answer is 3 + 2i.

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remember i^2 = -1 .

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[tex](a+bi)^2=5+12i[/tex]

[tex]a^2+2abi-b^2=5+12i[/tex]

Now, since a and b are real, you know a^2-b^2 = 5, and 2abi = 12i. Therefore, you can solve the system of equations to find a and b, thus finding z.

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Unfortunately, it was only a matter of guessing (and reverse factoring).aisha said:can u plz tell me how you got that answer?

I simply used: (ai + b)^2 = 12i + 5

Expanding the equation: (ai)^2 + (ab)i + b^2 = 12i + 5

Knowing that i^2 = -1, this equation can be simplified further:

-(a^2) + 2(ab)i + b^2 = 12i + 5

so... therefore:

a*b must equal 12 and 2(b^2 - a^2) must equal 5

Make a system of equations and solve:

2ab = 12

b^2 - a^2 = 5

Solving, we find that a = 2 and b = 3

Input them into the original expanded equation (-(a^2) + 2(ab)i + b^2 = 12i + 5)

So:

-(2^2) + 2(2*3)i + 3^2 = 12i + 5

-4 + 12i + 9

12i + 5

There's an easier method to this, probably... sorry I can't really help you out.

(EDIT: This came 3 min. after nolachrymose made a post... I'm really slow at this.)

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Phreak everything makes sense except for where did u get a=2 b=3? what did u solve and how? Im so dumb sorry lol I really dont like math.

Thanks Nolachrymose I would have never figured this out without u and Phreak thanks guys,

Thanks Nolachrymose I would have never figured this out without u and Phreak thanks guys,

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- #11

Gokul43201

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And b^2 - a^2 = 5, so 36/a^2 - a^2 = 5. This is just a quadratic in a^2. Solve it to find a^2, and hence a and b.

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