does anyone know how to find the square root of 5+12i ?
Try asking yourself the same question written differently:
Can you find a number z such that z*z = 5 + 12i?
That sounds easier but im not sure how to figure that out.
This was a multiple choice question so the answer is 2+i
I dont know how they got that!!
Actually... no, that's wrong. The answer is 3 + 2i.
If it's multiple choice, then it's even easier.
You say one of the choices was 2+i. Well, what is (2+i)*(2+i)? Is it 5+12i?
Do you know of a way to write down an arbitrary complex number, z, in terms of two (real) variables? If so, then you can compute what z^2 is...
can u plz tell me how you got that answer?
remember i^2 = -1 .
Well, you know that z is a complex number in the form a+bi. Therefore, you can say this:
Now, since a and b are real, you know a^2-b^2 = 5, and 2abi = 12i. Therefore, you can solve the system of equations to find a and b, thus finding z.
Unfortunately, it was only a matter of guessing (and reverse factoring).
I simply used: (ai + b)^2 = 12i + 5
Expanding the equation: (ai)^2 + (ab)i + b^2 = 12i + 5
Knowing that i^2 = -1, this equation can be simplified further:
-(a^2) + 2(ab)i + b^2 = 12i + 5
a*b must equal 12 and 2(b^2 - a^2) must equal 5
Make a system of equations and solve:
2ab = 12
b^2 - a^2 = 5
Solving, we find that a = 2 and b = 3
Input them into the original expanded equation (-(a^2) + 2(ab)i + b^2 = 12i + 5)
-(2^2) + 2(2*3)i + 3^2 = 12i + 5
-4 + 12i + 9
12i + 5
There's an easier method to this, probably... sorry I can't really help you out.
(EDIT: This came 3 min. after nolachrymose made a post... I'm really slow at this.)
Phreak everything makes sense except for where did u get a=2 b=3? what did u solve and how? Im so dumb sorry lol I really dont like math.
Thanks Nolachrymose I would have never figured this out without u and Phreak thanks guys,
You have ab = 6, so b = 6/a
And b^2 - a^2 = 5, so 36/a^2 - a^2 = 5. This is just a quadratic in a^2. Solve it to find a^2, and hence a and b.
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