- #1

ny_aish

- 21

- 0

I got the tension in the rope which is 440N, I am having trouble finding the Direction.

° (counterclockwise from x-axis) ?

I tried 1/cos of 164/440...its wrong

]

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- Thread starter ny_aish
- Start date

- #1

ny_aish

- 21

- 0

I got the tension in the rope which is 440N, I am having trouble finding the Direction.

° (counterclockwise from x-axis) ?

I tried 1/cos of 164/440...its wrong

]

- #2

lightgrav

Homework Helper

- 1,248

- 30

how did you get 440 N?

you _should_ keep vertical Forces and horizontal Forces separate .

you _should_ keep vertical Forces and horizontal Forces separate .

- #3

ny_aish

- 21

- 0

i will look thru my notes and see how i came to it.

- #4

ny_aish

- 21

- 0

So x- direction....-447N*cos(12) + T2*cos(θ2) = 0...So T2*cos(θ2) = 437.2 [eqn 1]

and in the y- direction 447*sin(12) + T2*sin(θ2) - 146 = 0..

so T2*sin(θ2) = 146 - 447*sin(12) = 53.1 [eqn 2]

Now divide eqn 2 by eqn 1 giving sin(θ2)/cos(θ2) = 53.1/437.1

or tan(θ2) = 0.1214....so θ2 = arctan(0.1214) = 6.92o

Now plug back into eqn 1 to get T2...T2 = 437.1/cos(6.92) = 440N

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