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TSN79

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- Thread starter TSN79
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TSN79

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- #2

iNCREDiBLE

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TSN79 said:The drawing below shows an angle A that I'm suppsosed to find. My book does this;

[tex]sin A=\frac{530-160}{2\cdot505}=0,366[/tex]

I am not able to follow the logic in how this would give me the sine of A...would love it if someone could help me out!

Shouldn't it be tan A?

- #3

LeonhardEuler

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Are you sure they don't mean tanA? Thats what it seems like.

- #4

TSN79

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Not according to my book...

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TSN79

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LeonhardEuler

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radou

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According to the first picture, [tex]sinA=\frac{185}{\sqrt{505^2+185^2}}[/tex] ...

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TSN79

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- #11

LeonhardEuler

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