# Find the angle

The drawing below shows an angle A that I'm suppsosed to find. My book does this;

$$sin A=\frac{530-160}{2\cdot505}=0,366$$

I am not able to follow the logic in how this would give me the sine of A...would love it if someone could help me out!

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• angle.jpg
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TSN79 said:
The drawing below shows an angle A that I'm suppsosed to find. My book does this;

$$sin A=\frac{530-160}{2\cdot505}=0,366$$

I am not able to follow the logic in how this would give me the sine of A...would love it if someone could help me out!

Shouldn't it be tan A?

LeonhardEuler
Gold Member
Are you sure they don't mean tanA? Thats what it seems like.

Not according to my book...

You are able to find the same angle in several places here, I just didn't draw them in, it might be calculated in reference to one of these places...?

LeonhardEuler
Gold Member
No, that can't be it. You can calculate sin (A) based on this picture to be about .344. It will be the same no matter where you calculate it from. Either the picture or the equation is a misprint.

If the book says sin A. Then the picture must look like this:

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• real.JPG
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I've included some more details on the drawing now. I'm not sure, but would the angle on the right wheel also be A? The same number data still applies, the 505 is the difference between the two wheels axles.

#### Attachments

• angle.jpg
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According to the first picture, $$sinA=\frac{185}{\sqrt{505^2+185^2}}$$ ...