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Introductory Physics Homework Help
Find the area and length of a gold leaf
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[QUOTE="MachineInTheStone, post: 6126581, member: 656883"] [h2]Homework Statement [/h2] Gold, which has a density of 19.32 g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. [B](a)[/B] If a sample of gold with a mass of 3.872 g, is pressed into a leaf of 5.372 μm thickness, what is the area of the leaf? [B](b)[/B] If, instead, the gold is drawn out into a cylindrical fiber of radius 2.300 μm, what is the length of the fiber?[h2]Homework Equations[/h2] d = m/v v = pi * r^2 * L v = l*w*h [h2]The Attempt at a Solution[/h2] d = m/v[/B] [Part A] 1) 19.32 g / 1 cm^3 = 3.872g / v v = 4.98967 cm^3 2) 5.372 micrometer * 1 cm / 10,000 micrometer = 0.0005372 cm 3) 4.98967 cm^3 / 0.0005372 cm = 9288 cm^2 4) 9288 cm^2 * 1 m^2 / 10,000 cm^2 = 0.9288 m^2 [part B] 1) 2.300 μm * 1 cm / 10,000 μm = 0.00023 cm 2) v = pi * r^2 * L Since v = 4.98967 cm^3 ... 4.98967 cm^3 = pi * (0.00023 cm)^2 * L 4.98967 cm^3 = 0.0000001662 cm^2 * L L = 30022100 cm 3) 30022100 cm * 1 m / 0.01 cm = 3,002,210,000 m Are part A and B correct? B seems totally wrong! [/QUOTE]
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Introductory Physics Homework Help
Find the area and length of a gold leaf
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