Find a parametrization of the curve x^{2/3}+y^{2/3}=1 and use it to compute the area of the interior. What I did was y=(1-x^{2/3})^{3/2} I then integrated this function from 0 to 1 (using maple since it is a crazy integral) and got the answer to be 3/32 [tex]\pi[/tex]. However this is wrong, I probably wasn't suppose to do it the way I did anyway considering that the integral is so complicated. So what should I do? I am learning Green's theroem right now if that helps, although I may have skipped ahead in it a bit I'm not sure. Thanks. Edit: Hm ok I have figured out what to do, the answer is 3/8 pi. How come my original answer is 1/4 of this though?
Hi mmmboh! They want you to use a parametrisation. For example, if it were x^{2}+y^{2}=1, you'd use x = cosθ, y = sinθ.