# Find the Area of the Interior

1. Feb 15, 2010

### mmmboh

Find a parametrization of the curve x2/3+y2/3=1 and use it to
compute the area of the interior.

What I did was y=(1-x2/3)3/2

I then integrated this function from 0 to 1 (using maple since it is a crazy integral) and got the answer to be 3/32 $$\pi$$.

However this is wrong, I probably wasn't suppose to do it the way I did anyway considering that the integral is so complicated.

So what should I do? I am learning Green's theroem right now if that helps, although I may have skipped ahead in it a bit I'm not sure.

Thanks.

Edit: Hm ok I have figured out what to do, the answer is 3/8 pi. How come my original answer is 1/4 of this though?

Last edited: Feb 15, 2010
2. Feb 15, 2010

### tiny-tim

Hi mmmboh!
They want you to use a parametrisation.

For example, if it were x2+y2=1, you'd use x = cosθ, y = sinθ.