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Find the area of the surface obtained by rotating the curve

  1. Feb 26, 2012 #1
    1. The problem statement, all variables and given/known data
    Find the area of the surface obtained by rotating the curve x = sqrt(a^2+y^2), 0≤ y≤a/2 about the y -axis.



    2. Relevant equations

    S = ∫0a/2 2pi x sqrt(1+(g'(y))^2) dy


    3. The attempt at a solution

    the answer is
    2pi (a/2)sqrt(a^2/(a^2-(a/2)^2)) sqrt(a^2-(a/2)^2)


    Nevermind I found out how to solve this question.
    Thank you Physics Forum this website help me solve a lot of my math hw besides this one.
    However I do not know how to delete this post.
    Administrator please delete this post if necessary.
    Thank you
     
    Last edited: Feb 26, 2012
  2. jcsd
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