A ball is projected upward at time = 0.0 s, from a point on a roof 10 m above the ground. The ball rises, then falls and strikes the ground. The initial velocity of the ball is 98.8 m/s Consider all quantities as positive in the upward direction. The average velocity of the ball, during the first 8.79s is closest to:
The Attempt at a Solution
We know that our intial velocity = 98.8m/s , and out final velocity = 0m/s
they are asking for the average velocity of the ball during the first 8.79 seconds. So I first tested out the equations which included v0,vx, t, and g.
What I tried doing at first was I tried to find the time it took for the ball to hit the ground.
so I used the formula x=xo+(v0x)t-1/2gt^2
Used the quadratic formula to solve for t and got t = 0.0493s
Since the average velocity is x2-x1/t2-t1
I tried 98.8-0/0.0493-8.79 and got -11.30.
Im so confused can someone explain to me how to get the correct answer.
Which is +56 m/s