Ok, here is my dilemma: A flight attendant pulls her 70.0 N flight bag a distance of 253 m along a level airport floor at a constant velocity. The force she exerts is 40.0 N at an angle of 52 degrees above the horizontal. Find the following: a) the work she does on the flight bag b) the work done on the flight bag c) the coefficient of kinetic friction between the flight bag and the floor What I did for a was, I multiplied the force of the bag (70)*the distance (253)*cos(theta). For the answere I got 10903.4 J. Then for b, I did the same thing, except used 40, and I got 6230.5 Am I doing this right so far? For c, I have no clue how to solve for the coefficient of kinetic friction. Whenever I try an equation, it comes out greater than one, or, I have another variable to solve for. Is there something that I am forgettting in the equation?