(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

=[tex]\frac{-3x^{4}}{(4x-8)^{1/2}}[/tex]

Is it actually correct, I'm not sure if it's correct, still.

2. Relevant equations

Quotient Rule and Chain Rule

3. The attempt at a solution

=[tex]\frac{-3x^{4}}{(4x-8)^{1/2}}[/tex]

=[tex]\frac{(-12x^{3})(4x-8)^{1/2}-(-3x^{4})(1/2)(4x-8)^{-1/2}(4)}{[(4x-8)^{1/2}]^{2}}[/tex]

=[tex]\frac{-12x^{3}(4x-8)^{1/2}+6x^{4}(4x-8)^{-1/2}}{(4x-8)}[/tex]

=[tex]\frac{-6x^{3}(2(4x-8)^{1/2}-x)}{(4x-8)^{3/2}}[/tex]

I'm not sure if it's correct up to here, but the [tex](4x-8)^{1/2}[/tex] isn't working. If there was no [tex]^{1/2}[/tex] it would work something like this:

=[tex]\frac{-6x^{3}(8x-16-x)}{(4x-8)^{3/2}}[/tex]

=[tex]\frac{-6x^{3}(7x-16)}{(4x-8)^{3/2}}[/tex]

But still unsure how they get the -3 in front and not -6 like I got.

Answer:

=[tex]\frac{-3x^{3}(7x-16)}{(4x-8)^{3/2}}[/tex]

Any help is appreciated. Thank you!

Look 2 posts lower for CLEARED UP version!

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# Homework Help: Find The Derivative

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