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Find the distance

  1. Jun 6, 2009 #1
    1. The problem statement, all variables and given/known data
    Approximately 0.1 of the bacteria in an adult human's intestines are Escherichia coli. These bacteria have been observed to move with speeds up to 15 and maximum accelerations of 166 . Suppose an E. coli bacterium in your intestines starts at rest and accelerates at 151 .
    How much distance is required for the bacterium to reach a speed of 12 ?

    2. Relevant equations
    d=vt
    t=v/a
    v^2=v0^2+2ax


    3. The attempt at a solution
    i used v^2=v0^2+2ax
    so v0 is 0 (i thiink)
    12^2=2(151)x
    x=.48
    is this correct??
     
  2. jcsd
  3. Jun 6, 2009 #2

    LowlyPion

    User Avatar
    Homework Helper

    Welcome to PF.

    Depending on if your units match, it looks OK.
     
  4. Jun 6, 2009 #3
    thanks it was correct...could you help me with one more problem?
     
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