- #1

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a.) r(t) = <ln(6t), sqrt(t+14), 1/sqrt(16-t)>

i dont extactly know how to approach this, can someone give me a hint or two

- Thread starter Whatupdoc
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- #1

- 99

- 0

a.) r(t) = <ln(6t), sqrt(t+14), 1/sqrt(16-t)>

i dont extactly know how to approach this, can someone give me a hint or two

- #2

- 70

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- #3

- 99

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[tex] t \geq -14[/tex]

[tex] t \leq 16[/tex]

right? so the domain should be from [-14,16]

[tex] t \leq 16[/tex]

right? so the domain should be from [-14,16]

- #4

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You're on the right track, but what about the ln(6t) function?

- #5

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t cannot equal to 0 for ln(6t). so should it be [-14,0) U (0, 16]

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