- #1

Whatupdoc

- 99

- 0

a.) r(t) = <ln(6t), sqrt(t+14), 1/sqrt(16-t)>

i don't extactly know how to approach this, can someone give me a hint or two

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- Thread starter Whatupdoc
- Start date

- #1

Whatupdoc

- 99

- 0

a.) r(t) = <ln(6t), sqrt(t+14), 1/sqrt(16-t)>

i don't extactly know how to approach this, can someone give me a hint or two

- #2

Brinx

- 70

- 1

- #3

Whatupdoc

- 99

- 0

[tex] t \geq -14[/tex]

[tex] t \leq 16[/tex]

right? so the domain should be from [-14,16]

[tex] t \leq 16[/tex]

right? so the domain should be from [-14,16]

- #4

Brinx

- 70

- 1

You're on the right track, but what about the ln(6t) function?

- #5

Whatupdoc

- 99

- 0

t cannot equal to 0 for ln(6t). so should it be [-14,0) U (0, 16]

- #6

Brinx

- 70

- 1

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