Find the electric potential

The Attempt at a Solution To find the electric potential at a distance of 1.00 cm from a proton, we can use the formula V = kQ/r, where k is the Coulomb's constant, Q is the charge of the proton, and r is the distance from the proton. Plugging in the values, we get V = (9x10^9 N*m^2/C^2)(1.6x10^-19 C)/(0.01 m) = 1.44x10^6 V. To find the potential difference between two points that are 1.00 cm and 2.00 cm from the proton, we can use the formula delta V = V2 -
  • #1
shinobi12
16
0

Homework Statement


(a) Find the electric potential at a distance of 1.00 cm from a proton. (b) what is the potential difference between two points that are 1.00 cm and 2.00 cm from a proton?


Homework Equations



I know delta V has to be set equal to something but I am not sure what


The Attempt at a Solution



Im not certain of the method to go about this problem. Please Help.
 
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  • #2
Hi shinobi12,

shinobi12 said:

Homework Statement


(a) Find the electric potential at a distance of 1.00 cm from a proton. (b) what is the potential difference between two points that are 1.00 cm and 2.00 cm from a proton?


2. Homework Equations


What is the formula for the electric potential of a point charge?
 
  • #3


I would approach this problem by first understanding the concepts of electric potential and potential difference. Electric potential is a measure of the electric potential energy per unit charge at a given point in an electric field. It is usually denoted by the symbol V and is measured in volts (V). Potential difference, also known as voltage, is the difference in electric potential between two points in an electric field.

To find the electric potential at a distance of 1.00 cm from a proton, we can use the equation V = kQ/r, where k is the Coulomb's constant, Q is the charge of the proton, and r is the distance from the proton. Plugging in the values, we get V = (9 x 10^9 Nm^2/C^2) x (1.6 x 10^-19 C) / (0.01 m) = 1.44 x 10^7 V. This means that at a distance of 1.00 cm from the proton, the electric potential is 1.44 x 10^7 V.

To find the potential difference between two points that are 1.00 cm and 2.00 cm from a proton, we can use the equation ΔV = V2 - V1, where V2 is the electric potential at the second point and V1 is the electric potential at the first point. Using the values we calculated earlier, we get ΔV = (1.44 x 10^7 V) - (7.20 x 10^6 V) = 7.20 x 10^6 V. This means that the potential difference between the two points is 7.20 x 10^6 V.

In summary, to find the electric potential and potential difference for a proton at a given distance, we can use the equations V = kQ/r and ΔV = V2 - V1, respectively. These equations are derived from the basic principles of electrostatics and Coulomb's law. I hope this helps in solving the problem.
 

1. What is electric potential?

Electric potential is a measure of the electric potential energy per unit charge at a specific point in an electric field.

2. How is electric potential different from electric field?

Electric potential is a scalar quantity that describes the potential energy per unit charge at a specific point, while electric field is a vector quantity that describes the force experienced by a charge at a specific point in the electric field.

3. How is electric potential calculated?

Electric potential can be calculated using the equation V = kQ/r, where V is the electric potential, k is the Coulomb's constant, Q is the charge, and r is the distance from the charge to the point where the potential is being measured.

4. What is the unit of electric potential?

The unit of electric potential is volts (V), which is equivalent to joules per coulomb (J/C).

5. How is electric potential used in practical applications?

Electric potential is used in various practical applications, such as in the design of electrical circuits, motors, and generators. It is also used in electrostatics experiments and in the study of the behavior of electric charges in different materials.

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