- #1
luigihs
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Find the equation of the straight line joining points (-1,1) and (2,5)
m = y1 - y2 / x1 - x2
5 - 1 / 2 - (-1) = 4/3
y - 1 = 4/3( x + 1 )
y = 4/3x + 4/3 + 1
y = 4/3x + 5/3< --- this is my attempt solution but I think is wrong! because on the back of my maths book the answer is 3y = 4x + 7 so I don't know what formula I have to use.
m = y1 - y2 / x1 - x2
5 - 1 / 2 - (-1) = 4/3
y - 1 = 4/3( x + 1 )
y = 4/3x + 4/3 + 1
y = 4/3x + 5/3< --- this is my attempt solution but I think is wrong! because on the back of my maths book the answer is 3y = 4x + 7 so I don't know what formula I have to use.