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Find the equations of the tangent line, normal plane and osculating plane to the curve at the point

  1. Oct 22, 2014 #1

    s3a

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    1. The problem statement, all variables and given/known data
    Find the equations of the tangent line, normal plane and osculating plane to the curve

    r(t) = -2sin(t) i + 2cos(t) j + 3 k

    at the point corresponding to t = π/4.

    2. Relevant equations
    T
    ^(t) = r'(t) // ||r'(t)||
    u = a i + b j + c k, ||u|| = √(a^2 + b^2 + c^2)
    N^(t) = T^(t) / ||T^(t)||
    B^ = T^ × N^

    The osculating plane is plane formed by unit normal and unit tangent vectors where the unit binormal vector is the vector normal to the osculating plane.

    The normal plane is formed by the unit normal and unit binormal vectors and the unit tangent vector is the vector normal to the normal plane.

    3. The attempt at a solution
    N
    ^(t) = sin(t) i - cos(t) j

    B
    (t) = k (technically independent of t)

    This was a question on a quiz I received, and I'm studying for an exam now, and I have the following three questions.:
    1. Would the tangent line be represented by P= a ⋅ T^(π/4) + [r(t) - r(π/4)] (where a is some scalar)?
    2. Would the normal plane be represented by T^(pi/4) ⋅ (r(t) -r(π/4)) = 0?
    3. Would the osculating plane be represented by B^(π/4) ⋅ (r(t) - r(π/4)) = 0?

    Any input would be GREATLY appreciated!
     
  2. jcsd
  3. Oct 23, 2014 #2
    I think your equation defining the unit normal is wrong -it should have primes(derivatives) rather than hats on the rhs.
    Then:
    1) Close but, The tangent line should have a single parameter; is it a or t? Try to picture: you start at r(π/4) and add an arbitrary amount (a) along the tangent vector.
    2) A plane should have 2 degrees of freedom; you are parametrizing it by t which gives only 1. Let r(t) be free, you are already constraining the plane to be normal to the tangent, and to pass through r(π/4).
    3) Yes, but , same problem as in 2.
     
  4. Dec 5, 2014 #3

    s3a

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    Sorry for the very-delayed response. (I have so much work that it takes time to get ahead of it so that I can do other things such as answer forum posts.)

    Okay, so the equation for the unit normal should be N^(t) = [d/dt T^(t)] / || d/dt [T^(t)] ||, right?

    1) So, would the tangent line be correctly represented by l_T = r(pi/4) + k * T^(π/4) ⇒ l_T = <–2,0,3> + k * <–√(2)/2, –√(2)/2, 0>? (where k is some scalar)

    2) So, would the normal plane be correctly represented by <–√(2)/2, –√(2), 0> ⋅ <x – –2, y – 0, z – 3> = 0?

    3) So, would the osculating plane be correctly represented by <0, 0, 1> ⋅ <x - -2, y – 0, z – 3> = 0?
     
  5. Dec 16, 2014 #4
    Right.
    1) lhs of ⇒ is correct, but r(pi/4) seems wrong.
    2) Form is correct, but seems the numbers are wrong.
     
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