1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Find the formula of the level curve (scalar) for the graph T(x,y) = (2x+y)/(x^2 -y^2)

  1. Mar 30, 2009 #1
    Hi this is the question that I am unsure about....

    Find and then sketch the level curves of the scalar field T(x,y) = (2x+y)/(x^2 -y^2) for;
    T = -1
    T = -0.5
    T = 0
    T = 0.5
    T = 1

    I am unsure about these answers which I got by subbing each of the values into T(x,y)

    1) T = -1

    After gathering x and y values on one side of the equation and completeing the square I got;

    (x + 1)^2 -(y - 0.5)^2 = 3/4 ....

    I am unsure about what kind of graph this is because I know that a hyperbola should be equal to 1 and this isn't.

    T = -0.5

    For this one I got (x + 2)^2 -(y - (0.5))^2 = (15/4)

    T = 0
    Finally one I could do :)

    y = 2x

    (x - 2) ^2 - (y +1)^2 = 3

    T = 1
    (x - 1)^2 - (y - 1/2)^2 = 3/4

    I am pretty sure that I got the equations correct but I would appreciate if someone could help me with;

    a) Explaining how I draw this since it is not in the form of a hyperbola ie not = 1.

    b) What these mean?
  2. jcsd
  3. Mar 31, 2009 #2


    User Avatar
    Science Advisor
    Homework Helper

    Re: Find the formula of the level curve (scalar) for the graph T(x,y) = (2x+y)/(x^2 -

    What is the equation for a circle of radius r and center point (a, b)?
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook