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I Find the General solution of H.D.E

  1. Feb 13, 2017 #1
    ((2(xy)^1/2) - y)y' + x dy = 0

    ive been at it for hours, substituting y=ux but im not sure if its definable to have both dy and y'. did the teacher just make a mistake?
     
  2. jcsd
  3. Mar 2, 2017 #2
    The mistake is in the equation itself. You wrote ((2(xy)^1/2) - y)y' + x dy = 0 which is non-sens : the first term is finite while the second term is infinitesimal.
     
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