Find the General solution of H.D.E

  • #1
((2(xy)^1/2) - y)y' + x dy = 0

ive been at it for hours, substituting y=ux but im not sure if its definable to have both dy and y'. did the teacher just make a mistake?
 

Answers and Replies

  • #2
798
34
The mistake is in the equation itself. You wrote ((2(xy)^1/2) - y)y' + x dy = 0 which is non-sens : the first term is finite while the second term is infinitesimal.
 

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