1. The problem statement, all variables and given/known data You want to know the height of a cliff so you throw a rock off the edge with initial speed v0 = 42 m/s upwards, inclined at an angle θ = 27° with respect to the horizontal. You have a friend that records the time that it takes for the rock to hit the bottom of the canyon below. It takes 7.6 s for the rock to hit the bottom of the canyon from when you throw it. 2. Relevant equations v0x = v0*cos(theta) v0y = v0*sin(theta) ay = -g ax = 0 vy(t) = v0*sin(theta) - g*t vx(t) = v0*cos(theta) x(t) = h + v0*sin(theta)*t - 1/2*g*t^2 y(t) = v0*cos(theta)*t h = height of the cliff v = velocity v0 = initial velocity a = acceleration 3. The attempt at a solution I am just confused about how to find the height of the cliff. I can't use the initial time because the initial time is zero. I tried solving for the x-distance at the final time. but I don't know how that would help. Any suggestions please?!?!