Find the hysteresis loss in the magnetic material

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Discussion Overview

The discussion revolves around calculating hysteresis loss in a magnetic material, specifically focusing on the energy loss per cycle and the factors influencing it, such as flux density and frequency. Participants explore the mathematical relationships involved in determining these losses.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant seeks confirmation on their calculation of hysteresis loss, indicating a desire for validation of their approach.
  • Another participant states that the hysteresis energy loss is 300 joules per cycle per cubic meter at a maximum flux density of 1.2 T, suggesting that the area of the hysteresis loop is 300.
  • A participant provides a formula for calculating hysteresis loss, Ph = A * V * f, and applies it to find Ph when the flux density is 0.8 T, frequency is 60 Hz, and volume is 40 cm3.
  • Some participants agree with the calculation of Ph = 0.376 W based on the provided parameters and formulas.

Areas of Agreement / Disagreement

There is agreement among some participants regarding the calculation of hysteresis loss as 0.376 W, but the initial question of confirming the overall approach remains open, as not all aspects of the discussion have been resolved.

Contextual Notes

The discussion does not clarify the assumptions behind the values used in the calculations, such as the choice of frequency or the specific conditions under which the hysteresis loss is measured.

Fatima Hasan
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Homework Statement
A sample of a magnetic material is known to have a hysteresis energy loss of 300 joules per cycle per cubic meter when the maximum flux density is 1.2 T . Find the hysteresis loss in the magnetic material if the flux density is 0.8 T , the volume of the magnetic material is 40 cm^3 , and the frequency of operation is 60 Hz . The Steinmetz constant is 1.6.
Relevant Equations
Equations are attached below.
5E%7B-6%7D%29*0.8%5E%7B1.6%7D%20%5C%5C%5C%5C%3D156.gif


That's what I've got , but I want to confirm my answer.
Any help would be greatly appreciated !
 

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Since the hysteresis energy loss is 300 joules per cycle per cubic meter when the maximum flux density is 1.2 T , the area of the hysteresis loop should be 300 at maximum flux density is 1.2 T, which means that just A=300.
:flashlight:
 
alan123hk said:
Since the hysteresis energy loss is 300 joules per cycle per cubic meter when the maximum flux density is 1.2 T , the area of the hysteresis loop should be 300 at maximum flux density is 1.2 T, which means that just A=300.
:flashlight:
So ,
Ph = A *V *f
V = 1 m^3
f = 1 Hz
A = 300 joules/ m^3 cycle
Ph = 300 W
Ph = Kh * f * Bmax^n * V
300 = Kh * 1*1.2^(1.6)*1
Solve for Kh = 224.09
Ph when the flux density = 0.8 T , f=60 Hz and V = 40 cm^3 :
Ph = 224.09 * 60 * (0.8)^1.6 * 40*10^(-3)
Ph = 0.376 W
Am I right now ?
 
Yes, I agree that Ph = 224.09 * 60 * (0.8)^1.6 * 40*10^(-6) = 0.376W is correct.
 
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alan123hk said:
Yes, I agree that Ph = 224.09 * 60 * (0.8)^1.6 * 40*10^(-6) = 0.376W is correct.
Thank you for your reply .
 

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