Integral (x / (x-1)^2) dx =(adsbygoogle = window.adsbygoogle || []).push({});

Let u = x, du = dx

Let dv = 1 / (x-1)^2 , v = -1 / x-1

uv - integral (vdu) dv

x ( -1 / (x-1) ) + integral (1 / x-1 ) =

x ( -1 / (x-1) ) + ln | x - 1 |

how come the answer is ( -1 / (x-1) ) + ln | x - 1 | ? what happend to the x in ->>> x ( -1 / (x-1) ) + ln | x - 1 | ?

Thank you in advance

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# Homework Help: Find the integral of x/(x-1)^2 with respect to x

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