- #1

- 31

- 0

[tex]\int\sqrt{e^{9x}} dx[/tex]

I figured that [tex]\int\sqrt{e^{9x}} dx[/tex] is equal to [tex]\int(e^{9x/2}) dx[/tex] so the integral should simply be [tex]e^{9x/2}+C[/tex]

Why isn't this correct?

- Thread starter 7yler
- Start date

- #1

- 31

- 0

[tex]\int\sqrt{e^{9x}} dx[/tex]

I figured that [tex]\int\sqrt{e^{9x}} dx[/tex] is equal to [tex]\int(e^{9x/2}) dx[/tex] so the integral should simply be [tex]e^{9x/2}+C[/tex]

Why isn't this correct?

- #2

- 77

- 1

Take the derivative of your answer and you'll see what you left out. Almost got it.

- #3

- 31

- 0

2/9! Thanks a ton.

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