Find the integral.

  • Thread starter 7yler
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  • #1
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Find the integral.
[tex]\int\sqrt{e^{9x}} dx[/tex]

I figured that [tex]\int\sqrt{e^{9x}} dx[/tex] is equal to [tex]\int(e^{9x/2}) dx[/tex] so the integral should simply be [tex]e^{9x/2}+C[/tex]

Why isn't this correct?
 

Answers and Replies

  • #2
Take the derivative of your answer and you'll see what you left out. Almost got it.
 
  • #3
31
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2/9! Thanks a ton.
 

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