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## Homework Statement

If [tex]F(x) = \frac{x}{x + 1}[/tex], then the inverse function, [tex]f^{-1}[/tex], is given by [tex]f^{-1}(x) = [/tex]

## Homework Equations

## The Attempt at a Solution

I've replaced F(x) with y, and switched the x and y variables. Where I'm having a problem is solving the resulting equation, here's what I've done so far.

[tex]x = \frac{y}{y + 1}[/tex],

[tex]xy + x = y[/tex],

[tex]x(y + 1) = y[/tex],

but as far as I can tell that just takes me back to where I started.

Also, I believe this is a question from an old AP Calculus exam. It's technically homework from a calculus class but seems to primarily involve algebra. Did I put it in the right forum or should it have gone in the precalculus forum? Thanks!