Find the KE of the following particles that each have a de Broglie wavelength of

Find the kinetic energy of the following particles that each have a de Broglie wavelength of 0.50 nm.?

(a) photons
____eV = 2480eV
(b) electrons
____eV
(c) neutrons
____eV
(d) α particles
____eV

i know E= hc/wavelength which = a and after that im stuck i know that the wavelength = h/p but i dont know how to solve the others with this

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i found be by taking hc/ lamda squared and dividing it by the momemtum squared

momentum p,
p = h/$\lambda$

total energy E :
E$^{2}$ = p$^{2}$c$^{2}$ + m$_{o}$ $^{2}$c$^{4}$

KE = E - m$_{o}$c$^{2}$