- #1
lkh1986
- 99
- 0
Find limit of f(x) when x approaches 0.
Given that f(x) is (1/x^3){(1+tanx)^0.5 - (1+sinx)^0.5}
The given answer is 0.25, but can somebody show me the solutions? I try the conjugate, and nothing works. Then I try to substitute t=(1+tanx)^0.5 and others, can't work, too.
Given that f(x) is (1/x^3){(1+tanx)^0.5 - (1+sinx)^0.5}
The given answer is 0.25, but can somebody show me the solutions? I try the conjugate, and nothing works. Then I try to substitute t=(1+tanx)^0.5 and others, can't work, too.