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[tex]\lim_{n\rightarrow \infty} \frac{2^{3n}}{3^{2n}}[/tex]
The answer is zero. All I can do is turn this infinity/infinity undeterminate form into a 0 times infinity indeterminate form. I also tried finding a creature strictly bigger than [itex]\frac{2^{3n}}{3^{2n}}[/tex] that has zero for a limit so that the answer would follow from the "sandwich theorem". But all my attempts let to infinity. For instance,
[tex]0\leq \frac{2^{3n}}{3^{2n}}\leq \frac{3^{3n}}{3^{2n}}=\frac{3^{2n}3^n}{3^{2n}}=3^n[/tex]
The answer is zero. All I can do is turn this infinity/infinity undeterminate form into a 0 times infinity indeterminate form. I also tried finding a creature strictly bigger than [itex]\frac{2^{3n}}{3^{2n}}[/tex] that has zero for a limit so that the answer would follow from the "sandwich theorem". But all my attempts let to infinity. For instance,
[tex]0\leq \frac{2^{3n}}{3^{2n}}\leq \frac{3^{3n}}{3^{2n}}=\frac{3^{2n}3^n}{3^{2n}}=3^n[/tex]
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