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Find the linearization of f(x)= x^1/3 at a=-64
so i am trying to use f(x)=f(a)+f'(a)(x-a)
f(a)=-4
f'(x)=1/3(x^-2/3)
f'(a)=-1/48
so i get -4+1/48(x+64)
is that right?
so i am trying to use f(x)=f(a)+f'(a)(x-a)
f(a)=-4
f'(x)=1/3(x^-2/3)
f'(a)=-1/48
so i get -4+1/48(x+64)
is that right?