Linearization of f(x)=x^1/3 at a=-64

In summary, linearization is the process of approximating a non-linear function with a linear function by finding the tangent line at a specific point. This is important because it allows us to analyze and solve problems involving non-linear functions using linear equations and techniques. The formula for linearization involves finding the derivative of the function and plugging it into the linearization formula. To linearize a function, we need to find its derivative, substitute the value of a, and plug the values into the linearization formula. For example, to linearize f(x)=x^1/3 at a=-64, we first find the derivative, substitute a=-64, and then plug the values into the linearization formula to get the linearized function L
  • #1
Rasine
208
0
Find the linearization of f(x)= x^1/3 at a=-64

so i am trying to use f(x)=f(a)+f'(a)(x-a)

f(a)=-4
f'(x)=1/3(x^-2/3)
f'(a)=-1/48

so i get -4+1/48(x+64)


is that right?
 
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  • #2
Well, you say f'(a)=-1/48 and you put +1/48 into the answer. Which is it?
 
  • #3
it is the latter
 
  • #4
Keerect. Then everything is ok.
 

What is linearization?

Linearization is the process of approximating a non-linear function with a linear function. This is done by finding the tangent line of the function at a specific point, which becomes the linear function.

Why do we need to linearize a function?

Linearization helps us to approximate the behavior of a non-linear function at a specific point, making it easier to analyze and understand. It also allows us to use linear equations and techniques to solve problems involving non-linear functions.

What is the formula for linearization?

The formula for linearization of a function f(x) at a point a is given by: L(x) = f(a) + f'(a)(x-a), where f'(a) represents the derivative of f(x) at x=a.

How do we linearize a function?

To linearize a function, we need to follow these steps:

  • Find the derivative of the function f'(x).
  • Substitute the value of a in f'(x) to find f'(a).
  • Plug the values of f(a) and f'(a) into the linearization formula L(x) = f(a) + f'(a)(x-a).

How do we linearize f(x)=x^1/3 at a=-64?

To linearize f(x)=x^1/3 at a=-64, we need to first find the derivative of the function, which is f'(x) = (1/3)x^(-2/3). Then, we can substitute a=-64 to find f'(a) = (1/3)(-64)^(-2/3) = -1/192. Finally, we can plug these values into the linearization formula L(x) = f(a) + f'(a)(x-a) to get L(x) = (-64)^(1/3) - (1/192)(x-(-64)), which simplifies to L(x) = x/4 + 16.

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