Find the Magnitude of the Magnetic Field in a moving loop

In summary, a conducting square loop with a side length of 0.30 m, oriented in the xy plane, moves at a constant speed of 2.0 m/s across the y-axis. While entering a uniform magnetic field that is unknown in magnitude and points in the positive z direction, the loop experiences a 0.63-V emf. Using the equation EMF = Blv, the magnitude of the magnetic field is calculated to be 1.05 T. The boundary of the magnetic field is the y-axis.
  • #1
Shinwasha
22
0

Homework Statement


A conducting square loop placed in the xy plane (oriented with its horizontal and vertical sides parallel to the x and y axes) moves to the right across the y-axis at a constant speed of 2.0 m/s, a 0.63-V emf is induced in the loop. If the side length of the loop is 0.30 m, what is the magnitude of the magnetic field?

Homework Equations


EMF = Blv

The Attempt at a Solution


So my EMF is 0.63, V = 2.0m/s, l = .30m and B is unknown

Thus
0.63 T*m^2*s^-1/(2.0m*s^-1 * .30m) = B
0.63 T/.6 = B

1.05 T = B

Not sure where I'm going wrong here.
 
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  • #2
Isn't your equation for a straight section of wire only, not for a square loop ?

And what is known of the magnetic field? A direction, where are the bounds, is it constant ?
 
  • #3
Magnetic Field is constant, the direction is into the positive z direction (guess I missed that part). I've tried to use ΔΦ/Δt, but not sure I did it right. Tried to take that fact it's traveling at 2m/s and the loop is 0.30 that

Δt= 0.30m/2m/s giving me 0.15 seconds to go through completely into the magnetic field.
a = 0.09m2
emf = 0.63 T*m2

Thus

0.63=(B)*(0.09)/0.15s

0.63*0.15/(0.09) = B

1.05 T = B

Gives the same answer.
 
  • #4
BvU has a good point here, when asking about the magnetic field's boundaries.

If the magnetic field and loop have a constant, perpendicular orientation [that is the field is perpendicular to the sides, parallel with the loop's normal], the loop's size is fixed, and the field is not changing with time, then the loop needs to be passing into or out of one of the magnetic field's boundaries in order to get an emf.

In short, something or other needs to be causing a change to the magnetic flux through the loop, otherwise an emf would not be occurring.

Is there anything more you can tell us about the magnetic field (boundary edges, etc.), or something about the loop changing size or orientation?

[Edit: Btw, the 1.05 T figure is correct if the loop is entering or leaving a boundary that is parallel with the loop's side, and spans the entire side. But if that doesn't give the correct answer, is that at least the correct description of the boundary?]
 
Last edited:
  • #5
collinsmark said:
BvU has a good point here, when asking about the magnetic field's boundaries.

If the magnetic field and loop have a constant, perpendicular orientation [that is the field is perpendicular to the sides, parallel with the loop's normal], the loop's size is fixed, and the field is not changing with time, then the loop needs to be passing into or out of one of the magnetic field's boundaries in order to get an emf.

In short, something or other needs to be causing a change to the magnetic flux through the loop, otherwise an emf would not be occurring.

Is there anything more you can tell us about the magnetic field (boundary edges, etc.), or something about the loop changing size or orientation?

[Edit: Btw, the 1.05 T figure is correct if the loop is entering or leaving a boundary that is parallel with the loop's side, and spans the entire side. But if that doesn't give the correct answer, is that at least the correct description of the boundary?]

The space to the right of the y-axis contains a uniform magnetic field of unknown magnitude that points in the positive z direction. As a conducting square loop placed in the xy plane (oriented with its horizontal and vertical sides parallel to the x and y axes) moves to the right across the y-axis at a constant speed of
2.0 m/s, a 0.63-V emf is induced in the loop.
If the side length of the loop is
0.30 m, what is the magnitude of the magnetic field?

Copied and pasted exactly. It's entering the magnetic field. That's all I get.

It's entering the magnetic field, nothing about magnetic field's boundaries.
 
  • #6
Shinwasha said:
The space to the right of the y-axis contains a uniform magnetic field of unknown magnitude that points in the positive z direction. As a conducting square loop placed in the xy plane (oriented with its horizontal and vertical sides parallel to the x and y axes) moves to the right across the y-axis at a constant speed of
2.0 m/s, a 0.63-V emf is induced in the loop.
If the side length of the loop is
0.30 m, what is the magnitude of the magnetic field?

Copied and pasted exactly. It's entering the magnetic field. That's all I get.

It's entering the magnetic field, nothing about magnetic field's boundaries.
The boundary is the y-axis.

For regions where x < 0, there is no magnetic field at all. For regions where x > 0, there is a magnetic field of unknown magnitude that points in the z direction. That's what was meant by saying, "the space to the right of the y-axis contains a uniform magnetic field of unknown [...]" That specifies the boundary, assuming that the space to the left of the y-axis contains 0 magnetic field. That's the assumption that I would make anyway.

That said, your answer of 1.05 T looks right to me. :smile:
 
  • #7
Shinwasha said:
That's all I get
Makes a big difference with post #1, though. I understand you didn't realize that when you posted, but it sure is a reminder that a complete and concise problem statement is extremely important, not only for yourself (to order your thoughts and get lined up for the equation gathering phase), but also to get adequate assistance !
And putting together the relevant equations is indispensable too - if necessary in more than one iteration.:rolleyes:
 

1. What is the equation for finding the magnitude of the magnetic field in a moving loop?

The equation for finding the magnitude of the magnetic field in a moving loop is B = μ0Iv/2R, where B is the magnetic field strength, μ0 is the permeability of free space, I is the current flowing through the loop, v is the velocity of the loop, and R is the radius of the loop.

2. How does the velocity of the loop affect the magnitude of the magnetic field?

The magnitude of the magnetic field is directly proportional to the velocity of the loop. This means that as the velocity increases, the magnetic field strength also increases.

3. What is the significance of the current in the equation for finding the magnitude of the magnetic field?

The current flowing through the loop plays a crucial role in determining the magnitude of the magnetic field. The larger the current, the stronger the magnetic field will be.

4. Can the magnitude of the magnetic field be negative?

No, the magnitude of the magnetic field cannot be negative. It is always a positive value that represents the strength of the magnetic field.

5. How does the radius of the loop affect the magnitude of the magnetic field?

The magnitude of the magnetic field is inversely proportional to the radius of the loop. This means that as the radius increases, the magnetic field strength decreases, and vice versa.

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