A uniform meter stick of mass M has a half-filled can of fruit juice of mass m attached to one end. The meter stick and the can balance at a point 12.5 cm from the end of the stick where the can is attached. When the balanced stick-can system is suspended from a scale, the reading on the scale is 2.79 N. Find the mass of the meter stick. Find the mass of the can of juice.(adsbygoogle = window.adsbygoogle || []).push({});

I divided the scale reading 2.79 N by 9.81 m(gravity) to find the total mass. I got 0.2844036697. I did this because the scale reading should be equal to the gravitation force (so I think).

Then I took the equation m1x1=m2x2. I used 0.875m for x1 and .125m for x2. I solved for m2. Then I used m1 + m1(7) = 0.2844036697 to find m1. Which I got 0.0305 which isn't right. Please tell me where I went or if I"m on the right track. If not please give me the formulas you used. Thank You.

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# Homework Help: Find the mass of the meter stick

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