1. The problem statement, all variables and given/known data Find the maximum and minimum values of the function f(x) = 2sin2x-2sinx on the interval [-pi, pi]] 2. Relevant equations first derivative 3. The attempt at a solution f'(x) = 4sinxcosx-2cosx 0 = 2cosx (2sinx-1) 0 = 2sinx-1, sinx = 1/2, x = pi/6, 5pi/6 0 = 2cosx, cosx = 0, x = pi/2 I got that MIN = -0.5 (plugged pi/6 and 5pi/6 into the original function) but I can't seem to find where MAX @4 is. Thank you! Thank you!