A sportscar, Fiasco I, can accelerate uniformly to 76 m/s in 30 s. Its maximum braking rate cannot exceed 0.60g. What is the minimum time required to go 1250 m, assuming the car begins and ends at rest?
a = v/t
v = d/t = [tex]\Delta[/tex]r/t
vavg = (vi + vf)/2 [when a is constant]
The Attempt at a Solution
accelrate1 = (76m/s) / 30s = 2.53 m/s^2
accelrate2 = - (0.60)g = - (0.6)(9.8N/kg) = -5.88N/kg = -5.88 m/s^2
ri = <0,0,0>m
rf = <1250,0,0>m
vi = <0,0,0>m/s
vf = <0,0,0>m/s
I tried breaking it up into two parts, the first being the acceleration and the second being the deceleration, but I cannot seem to get the correct answer.