The two forces F1 and F2 (shown in the figure) (i attached the figure hopefully I did it correctly) act on a 27.0 kg object on a frictionless tabletop. If F1=10.2N and F2= 16.0N, find the net force on the object and its acceleration for a and b
The Attempt at a Solution
If I'm approaching this correctly I believe its a simple vector addition problem?
for a I have:
this vector is = SQRT(-10.22 + -16.02) = 18.97N
19.97 = 27.0kg (a)
a= 0.70 m/s2
For b I have:
F2: x=0 y=16
F1: x=cos30 (10.2) = 8.8 y= sin30 (10.2) = -5.1
adding the x's together = 8.8
adding the y's together = 10.9
finding the vector= SQRT(8.82+ 10.92) = 14.0N
14.0 = 27.0 kg (a)
a= 0.52 m/s2
Does this look correct?? Or did I even approach this correctly??